In the real number system,the equation $\sqrt{x+3-4 \sqrt{x-1}}+\sqrt{x+8-6 \sqrt{x-1}}=1$ has

  • A
    no solution
  • B
    exactly two distinct solutions
  • C
    exactly four distinct solutions
  • D
    infinitely many solutions

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If $p$ and $q$ are distinct prime numbers and the equation $x^2 - px + q = 0$ has positive integers as its roots,then the roots of the equation are:

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